Answer:
The correct option is C. 13/14
Explanation:
![\text{Probability of drawing the first candy red = }(2)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/4bvmu1g9qb208n36v58nmuvywslnphth71.png)
Let the probability of drawing second candy red be x
![\text{Now, Probability of drawing the two candies red = }(13)/(35)](https://img.qammunity.org/2019/formulas/mathematics/high-school/pb0ebcedn7ftqd3n9cmwal03x26b1vtqnk.png)
So, Probability of drawing two candies red = Probability of drawing one candy red × Probability of drawing second candy red
![(13)/(35)=(2)/(5)* x](https://img.qammunity.org/2019/formulas/mathematics/high-school/s2b2s8d893pj4vj957qssn4u2thw7kshf3.png)
![\implies x = (13)/(35)* (5)/(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/64qjspzo0p15hr0zjpybpls7ynkkce3feg.png)
![\implies x = (13)/(14)](https://img.qammunity.org/2019/formulas/mathematics/high-school/tm4uj73jyolt9cwkzb1o6thvktl5jub8d0.png)
![\textbf{The probability of drawing second candy red = }\bf(13)/(14)](https://img.qammunity.org/2019/formulas/mathematics/high-school/yp8f5abwhl56tsofqcehjxvdwwpp4kbpt0.png)
Therefore, The correct option is C. 13/14