Question

The Punnett square shows the possible genotype combinations of two parents who are heterozygous for a particular trait.

What is the probability of the parents having a child who is homozygous dominant for this trait?

Group of answer choices

4. 25%

3. 75%

2. 0%

1. 50%

Answer 1

The probability of the parents having a child who is hzygous dominant for this trait is - 25%

In the given question, there is a particular character that has two alleles Y dominant allele and y recessive allele. Both parents are heterozygous for the trait that is encoded as Yy cross with Yy.

Cross between: Yy X YyIf both parents carry only one copy of a recessive gene, the likelihood of a child have the recessive trait is one in four.

Offspring are produced: YY: 2Yy: yyHozygous would be represented for dominant - YYthere is one YY out of 4 offsprings (1/4)*100 = 25% Thus, the correct probability would be - 25%