Question

Solve x2 + 3x + 1 = 0. (1 point)

a) x equals the quantity of 3 plus or minus square root 13 all over 2
b) x equals the quantity of negative 3 plus or minus square root 13 all over 2 c) x equals the quantity of negative 3 plus or minus square root 5 all over 2 d)x equals the quantity of 3 plus or minus square root 5 all over 2

Answer 1

`\huge\text{Hey there!}`

`\huge\textbf{Quadratic formula: }`

`\mathbf{x = (-b \pm √(b^2 - 2ac))/(2a)}`

`\huge\textbf{Looking for:}`

`\mathbf{x^2 + 3x + 1 = 0}`

`\huge\textbf{The conversion equation should look like:}`

`\mathbf{x = ((-3) \pm √((3)^2- 4(1)(1)))/(2(1))}`

`\huge\textbf{SIMPLIFY THAT!}`

`\mathbf{x = (-3\pm√(5))/(2)}`

`\huge\textbf{SIMPLIFY THAT AS WELL!}`

`\mathbf{x = -(3)/(2) + (1)/(2) √(5) \ or\ you\ could\ say \ x = - (3)/(2) + -(1)/(2)√(5)}`

`\huge\textbf{Your answer simplified to easier terms:}`

`\boxed{\mathbf{x = -(3)/(2) + (1)/(2) √(5) \ \boxed{\mathsf{or}} \ \ x = - (3)/(2) + -(1)/(2)√(5)}}\huge\checkmark`

`\huge\textbf{The synopsis of the answer: }`

`\mathbf{ c) \x \ equals \ the \ quantity \ of \ negative \ 3 \ plus \ or \ minus\ square\ root}\\\mathbf{5 \ all \ over \ 2}`

~
`\frak{Amphitrite1040:)}`

Answer 2

c) x equals the quantity of negative 3 plus or minus square root 5 all over 2

Explanation:

x^2 + 3x + 1 =0

using the quadratic formula

-b ± sqrt(b^2 -4ac)

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2a

-3 ± sqrt(3^2-4(1)(1))

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2(1)

-3 ±sqrt(9-4)

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2

-3±sqrt(5)

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2