Question

What are the x-intercepts of this function f(x)=x^2+5x-36?

Answer 1

f(x)=x2+5x−36f(x)=x2+5x-36
(0)=x2+5x−36(0)=x2+5x-36
x=4,−9x=4,-9
y=(0)2+5(0)−36y=(0)2+5(0)-36
y=0+0−36y=0+0-36
y=−36y=-36
These are the xx and yy intercepts of the equation y=x2+5x−36y=x2+5x-36.
x-int: (4,0),(−9,0)(4,0),(-9,0)
y-int: (0,−36)(0,-36)