Question

Mid chapter checkpoint 5th grade chapter 6 awser key

Answer 1

QUESTION 1

A common multiple is a number that is a multiple of two or more numbers.

For instance 18 is a common multiple of 2 and 3.

This is not the only common multiple.

QUESTION 2

A common denominator is a common multiple of two or more denominators.

For instance a common denominator for
`(1)/(2) ,(1)/(4)`

is 4

This is also not the only common denominator.

QUESTION 3

We were given;

`(8)/(9)+(4)/(7)`

We want to estimate the sum of the given fractions.

We collect LCM to obtain,

`=(8* 7+9*4)/(63)`

We multiply out in the numerator to obtain,

`=(56+36)/(63)`

We perform the addition in the numerator to obtain,

`=(92)/(63)`

We express the final answer as a mixed number to obtain,

`=1(29)/(63)`

QUESTION 4

The given expression is
`3(2)/(5)-(5)/(8)`.

Let us change the first first mixed number into an improper fraction to get,

`=(17)/(5)-(5)/(8)`

We collect LCM of the denominators which is 40 to obtain,

`=(8*17-5*5)/(40)`

We now multiply out in the numerator to get,

`=(136-25)/(40)`

We carry out the subtraction in the numerator to get,

`=(111)/(40)`

We express the final answer as a mixed number to obtain;

`=2(31)/(40)`

QUESTION 5

The given fraction is
`1(5)/(6)+2(2)/(11)`.

Let us first of all change each mixed number to improper fractions

`=(11)/(6)+(24)/(11)`

We now collect LCM of the denominators to obtain,

`=(11*11+24*6)/(66)`

We multiply in the numerator to get,

`=(121+144)/(66)`

This gives,

`=(265)/(66)`

`=4(1)/(66)`

QUESTION 6

The given fractions are;

`(1)/(6),(1)/(9)`.

The least common denominator is
`18`.

We obtain the equivalent fraction by multiplying the denominator and numerator of each fraction by a common factor that gives 18 in the denominator.

`(1*3)/(6*3),(1*2)/(9*2)`.

This gives us;

`(3)/(18),(2)/(18)`.

QUESTION 7

The given fractions are;

`(5)/(6),(3)/(8)`.

The least common denominator is
`24`.

We obtain the equivalent fraction by multiplying the denominator and numerator of each fraction by a common factor that gives 24 in the denominator.

`(5*4)/(6*4),(3*3)/(8*3)`.

This gives us;

`(20)/(24),(9)/(24)`.

QUESTION 8

The given fractions are;

`(3)/(8),(3)/(10)`.

The least common denominator is
`40`.

We obtain the equivalent fraction by multiplying the denominator and numerator of each fraction by a common factor that gives 40 in the denominator.

`(3*5)/(8*5),(3*4)/(10*40)`.

This gives us;

`(15)/(40),(12)/(40)`.

QUESTION 9

The given fractions are;

`(2)/(5),(1)/(10)`.

The least common denominator is
`10`.

We obtain the equivalent fraction by multiplying the denominator and numerator of each fraction by a common factor that gives 10 in the denominator.

`(2*2)/(5*2),(1*1)/(10*1)`.

This gives us;

`(4)/(10),(1)/(10)`.

QUESTION 10

The given fractions are;

`(1)/(9),(5)/(12)`.

The least common denominator is
`36`.

We obtain the equivalent fraction by multiplying the denominator and numerator of each fraction by a common factor that gives 36 in the denominator.

`(1*4)/(9*4),(5*3)/(12*3)`.

This gives us;

`(4)/(36),(3)/(36)`.

QUESTION 11

The given fractions are;

`(1)/(3),(2)/(7)`.

The least common denominator is
`21`.

We obtain the equivalent fraction by multiplying the denominator and numerator of each fraction by a common factor that gives 21 in the denominator.

`(1*7)/(3*7),(2*3)/(7*3)`.

This gives us;

`(7)/(21),(6)/(21)`.

QUESTION 12,

The given fraction is

`(11)/(18)-(1)/(6)`

The least common denominator is
`18`.

We collect LCD to obtain,

`=(11-3*1)/(18)`

This simplifies to;

`=(11-3)/(18)`

`=(8)/(18)`

`=(9)/(4)`

QUESTION 13

The given fraction is

`(2)/(7)+(2)/(5)`

The least common denominator is
`35`.

We collect LCD to obtain,

`=(2*5+2*7)/(35)`

This simplifies to;

`=(10+14)/(35)`

`=(24)/(35)`

QUESTION 14

The given fraction is

`(3)/(4)-(3)/(10)`

The least common denominator is
`20`.

We collect LCD to obtain,

`=(3*5-3*2)/(20)`

This simplifies to;

`=(15-6)/(20)`

`=(9)/(20)`