Answer: 3.5;0.4%
Explanation:
The number of defective screwdrivers that the quality inspector should expect would be calculated as:
= np
= 0.7% × 500
= 0.7/100 × 500
= 0.007 × 500
= 3.5
.
The error will be calculated as:
= √p(1-p)/n
= ✓0.007(1 - 0.007)/500
= 0.004
= 0.4%