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What is an equation of the line that passes through the points (3,-3) and (-3,-3)?

User Gnavi
by
6.0k points

1 Answer

2 votes
First find the gradient of the line
Change in y/change in x
-3–3/-3-3
0/-6
=0 ( so the gradient m is equal to zero)

Y=0x+c

Input the coordinates of one point to find c

-3=(0*3)+c
-3=c


So the equation is
Y= -3


User Sayan Malakshinov
by
5.2k points