Question

1. Two loudspeakers are placed 4.5 m apart. They produce the same sounds, in step, at a frequency of 829 Hz. Constructive interference is observed at point P, which is 5.30 m from one loudspeaker and a distance x from the other. Which is a possible value of x? Assume the speed of sound is 340 m/

a.6.60

b. 6.77

c. 6.80

d. 6.88

e. 6.53

2. Two loudspeakers are placed 6.0 m apart. They produce the same sounds, in step, across a frequency range of 252 Hz to 665 Hz. Point P is located 5.10 m from one loudspeaker and 3.60 m from the other. What frequency of sound from the two speakers will produce constructive interference at point P? Assume the speed of sound is 344 m/s.

a. 631
b. 401
c. 459
d. 573
c. 516

Answer 1

What was the answer? I go to Connexus too and I’m struggling in physics.

Answer 2

#1

speed of sound = 340 m/s

frequency = 829 Hz

wavelength of sound = speed / frequency

`\lambda = (340)/(829) = 0.41 m`

Now for constructive interference we know that

path difference of two waves = integral multiple of wavelength

`x - 5.30 = N\lambda`

`x = 5.30 + N\lambda`

if N = 3

`x = 6.53 m`

#2

speed of sound = 344 m/s

frequency range = 252 Hz - 665 Hz

wavelength of sound = speed / frequency

`\lambda = (344)/(f)`

Now for constructive interference we know that

path difference of two waves = integral multiple of wavelength

`5.10 - 3.60 = N\lambda`

`N\lambda = 1.5`

Now we will have

`\lambda = (v)/(f)`

`(1.5)/(N) = (344)/(f)`

by rearranging above terms we have

`f = (N(344))/(1.5) = 229.3N`

`f = 459 Hz`