Question

What is the equation of the line (in point-slope form) that is parallel to y−5= − 1 /3 (x+2) and passes through the point (6,−1)?

Answer 1

`y-(-1)=-(1)/(3)(x-6)`

Explanation:

Parallel lines have the same slope. The slope of the given line is
`-(1)/(3),` then the equation of the parallel line that passes through the point (6,-1) in point-slope form is

`y-(-1)=-(1)/(3)(x-6).`