1 Answer

Dan Zheng · Answer 1 · 2019-06-02T21:06:38+0000

Answer:

(A)
$F_N - mg\cos\theta$

Step-by-step explanation:

The net force perpendicular to the surface of the incline is the sum of the gravity force component, which is mgcos(theta), and the reactionary normal force caused by the surface of the incline. The sum is F_N - mgcos(theta) and is usually 0 which is why the object is not moving perpendicularly to the surface of the incline.

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