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Factor completely: 16-2x^3

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16-2x^3=2(8-x^3)=2(2^3-x^3)\\\\\text{use}\ a^3-b^3=(a-b)(a^2-ab+b^2)\\\\=2(2-x)(2^2+2x+x^2)\\\\=\boxed{2(2-x)(4+2x+x^2)}

User FZeiser
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