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Which is the center of a circle whose equation is x2+y2+4x-8y+11=0?

User Johangu
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2 Answers

0 votes

Answer:

-2,4

Explanation:

edge 2021

User Todd Grigsby
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7.8k points
2 votes

Answer:

Center (-2 , 4)

Explanation:

x^2 + 4x + y^2 - 8y = - 11

(x^2 + 4x + (4/2)^2 + (y^2 - 8y + (8/2)^2 ) = - 11 + 4 + 16

(x + 2)^2 + (y - 4)^2 = 9

Center (-2, 4)

User Pawneshwer Gupta
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7.8k points

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