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Write the coordinate point for the vertex of this parabola x^2=12y

User MDCore
by
6.2k points

2 Answers

1 vote

Answer:

(0,0)

Explanation:

User Erick T
by
5.9k points
7 votes

Answer:

(0,0)

Explanation:

the x coordinate for the vertex is at the line of symmetry

ax^2 +bx+c

the line of symmetry is at h =-b/2a

x^2 =12y

divide by 12

1/12 x^2 = y

a = 1/12 b=0 c=0

h = 0/(2* 1/12)

h =0

to find the y coordinate, substitute x=0 back in

y = 1/12 * 0 = 0

the vertex is (0,0)

User Bindrid
by
6.4k points