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Which is the equation of this circle in standard form

Which is the equation of this circle in standard form-example-1

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4 votes

Answer:

(x − 5.5)2 + (y − 4)2 = 12.25

Step-by-step explanation: Just took the test and got it right

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Which is the equation of this circle in standard form-example-1
User Comu
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4 votes

The equation of a circle in standard form:


(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

The center is a midpoint of MN. The formula of a midpoint:


\left((x_1+x_2)/(2);\ (y_1+y_2)/(2)\right)

We have M(2, 4) and N(9, 4). Substitute:


x=(2+9)/(2)=(11)/(2)=5.5\\\\y=(4+4)/(2)=(8)/(2)=4

Therefore we have the center (5.5, 4) → h = 5.5 and k = 4.

The radius of a distance between the center and M.

The formula of a distance between two points:


d=√((x_2-x_1)^2+(y_2-y_1)^2)

We have the points (5.5, 4) and (2, 4) Substitute:


d=√((4-4)^2+(2-5.5)^2)=√(0^2+(-3.5)^2)=√(3.5^2)=3.5

Substitute to the equation of a circle:


(x-5.5)^2+(y-4)^2=3.5^2\\\\\boxed{(x-5.5)^2+(y-4)^2=12.25}\to\boxed{C.}

User Jan Sila
by
8.2k points

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