Question

1. Find the percent of change when the price of a radio changes from $40.00 to $44.00.

a. 12% b. 10% c. 36.4% d. 40% 2. Find the percent of change when the price of an oven changes from $450 to $396.
a. 15% b. 14% c. 13% d. 12% 3. The top player’s scoring average changes from 20 points per game to 24 points per game.
a. 20% increase b. 25% decrease c. 16.7% increase d. 4% increase 4. At the start of the football season, Jorge weighed 150 pounds. At the end of the season, he weighed 138 pounds. What was the percent change in his weight?
a. 10% b. 12% c. 8.7% d. 8% 5. Sara raised her raw score on a math test from 40 to 60. What was the percent change in Sara's score?
a. 10% b. 20% c. 40% d. 50%

Answer 1

(1)

option-b

(2)

option-d

(3)

option-a

(4)

option-d

(5)

option-d

Explanation:

(1)

previous value =$40

new value =$44

so, change = new value - previous value

change =44-40

change =4

percent of change = ((change)/(previous value))*100

percent of change is

`=(4)/(40)* 100`

percent of change is 10%..................Answer

(2)

previous value =$450

new value =$396

so, change = new value - previous value

change =396-450

change =-54

percent of change = ((change)/(previous value))*100

percent of change is

`=(-54)/(450)* 100`

`=-12`

percent of change is -12%..................Answer

(3)

previous value =20

new value =24

so, change = new value - previous value

change =24-20

change =4

percent of change = ((change)/(previous value))*100

percent of change is

`=(4)/(20)* 100`

`=20`

percent of change is 20%..................Answer

(4)

previous value =150 pounds

new value =138 pounds

so, change = new value - previous value

change =138-150

change =-12

percent of change = ((change)/(previous value))*100

percent of change is

`=(-12)/(150)* 100`

`=-8`

percent of change is -8%..................Answer

(5)

previous value =40

new value =60

so, change = new value - previous value

change =60-40

change =20

percent of change = ((change)/(previous value))*100

percent of change is

`=(20)/(40)* 100`

`=50`

percent of change is 50%..................Answer

Answer 2

1. b) 10%

2. d) 12%

3. a) 20%

4. d) 8%

5. d) 50%

Explanation:

We will use percentage change formula to solve our given problems.

`\text{Percent change}=\frac{\text{Final value - Initial value}}{\text{initial value}}*100`

1. The percent of change when the price of a radio changes from $40.00 to $44.00.

`\text{Percent change}=(44-40)/(40)*100`

`\text{Percent change}=(4)/(40)*100`

`\text{Percent change}=(1)/(10)*100`

`\text{Percent change}=1*10=10`

Therefore, the price of radio increased by 10% and option b is the correct choice.

2. The percent of change when the price of an oven changes from $450 to $396.

`\text{Percent change}=(396-450)/(450)*100`

`\text{Percent change}=(-54)/(450)*100`

`\text{Percent change}=-0.12*100`

`\text{Percent change}=-12`

Therefore, the price of oven decreased by 12% and option d is the correct choice.

3. The top player’s scoring average changes from 20 points per game to 24 points per game.

`\text{Percent change}=(24-20)/(20)*100`

`\text{Percent change}=(4)/(20)*100`

`\text{Percent change}=4*5`

`\text{Percent change}=20`

Therefore, the player's scoring average increased by 20% and option a is the correct choice.

4. At the start of the football season, Jorge weighed 150 pounds. At the end of the season, he weighed 138 pounds.

[\text{Percent change}=\frac{138-150}{150}*100[/tex]

`\text{Percent change}=(-12)/(150)*100`

`\text{Percent change}=-0.08*100`

`\text{Percent change}=-8`

Therefore, the Jorge's weight decreased by 8% and option d is the correct choice.

5. Sara raised her raw score on a math test from 40 to 60.

`\text{Percent change}=(60-40)/(40)*100`

`\text{Percent change}=(20)/(40)*100`

`\text{Percent change}=20*2.5`

`\text{Percent change}=50`

Therefore, Sara's score on math test increased by 50% and option d is the correct choice.