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Marc sold 461 tickets for the school play student tickets cost 3$ and adult cost tickets cost 4$ Marc’s sales total is $1624 how many adult tickets did Marc sell

User WoooHaaaa
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2 Answers

5 votes

Final answer:

By creating a system of linear equations based on the total number of tickets and the total sales, we can use the elimination method to find that Marc sold 241 adult tickets.

Step-by-step explanation:

The question requires us to solve a system of linear equations where we have two variables representing the number of student tickets and adult tickets sold. Marc sold a total of 461 tickets for the school play, and the sales totaled $1624. Student tickets cost $3 each, and adult tickets cost $4 each. To find out how many adult tickets were sold, we'll denote the number of student tickets as 's' and the number of adult tickets as 'a'.

Step 1: Write the equations based on given information

  • The total number of tickets sold is 461: s + a = 461
  • The total sales from these tickets is $1624: 3s + 4a = 1624

Step 2: Solve the system of equations

You can use substitution or elimination method. In this case, we will use the elimination method to solve for 'a'.

  1. Multiply the first equation by 3, which gives us: 3s + 3a = 1383
  2. Subtract it from the second equation: (3s + 4a) - (3s + 3a) = 1624 - 1383, which simplifies to a = 241

So, Marc sold 241 adult tickets.

User Monzurul Shimul
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7.6k points
4 votes

Answer:

241 tickets

Step-by-step explanation:

1. Make a system of equations with x for student tickets and y for adult tickets:

3x+4y=1624

x+y=461

2. Solve for y as that is the amount of adult tickets that Marc sold:

3x+4y=1624

3x+3y=1383

y=241

User KungPhoo
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7.7k points