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1 vote
Kobe Bryant is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 83\%83% of the time.

What is the probability of Kobe Bryant making all of his next 6 free throw attempts?
Choose 1 answer:

a)(1−0.83)^6
b)0.83^6
c)6⋅0.83
d)6⋅(1−0.83)

User MitoRibo
by
8.2k points

1 Answer

5 votes

Answer:

b)0.83^6

probability of Kobe Bryant making all of his next 6 free throw attempts

=probability of Kobe Bryant making first free throw attempts x

probability of Kobe Bryant making second free throw attempts x

probability of Kobe Bryant making third free throw attempts x

probability of Kobe Bryant making fourth free throw attempts x

probability of Kobe Bryant making fifth free throw attempts x

probability of Kobe Bryant making sixth free throw attempts

= P(make 1) x P(make 2nd) x P(make 3rd) x P(make 4th) x P(make 5th)x P(make 6th) = 0.83^6



User Zmilan
by
7.9k points
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