Question

1. Is so hard for me it’s a before and after radio problem I can never do them

Answer 1

e = number of egg sandwiches

t = number of tuna sandwiches

since they're on a ratio of 2:3 then e/t = 2/3

`\bf e:t\qquad 2:3\qquad \cfrac{e}{t}=\cfrac{2}{3}\implies e=\cfrac{2t}{3}~\hfill \stackrel{\textit{then he made 15 more tuna ones}}{\cfrac{e}{t+15}~~=~~\cfrac{1}{3}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{doing some substitution for \underline{e}}}{\cfrac{~~(2t)/(3)~~}{t+15}=\cfrac{1}{3}}\implies \left( \cfrac{2t}{3} \right)3=(t+15)1\implies 2t=t+15 \\\\\\ \boxed{t=15}~\hspace{7em}e=\cfrac{2(15)}{3}\implies \boxed{e=10}~\hfill \boxed{\stackrel{total~e+t+15}{40}}`

Answer 2

Answer: 40

Explanation:

Let x represent the original ratio and y represent the final ratio:

Egg : Tuna

2x 3x

+15 15 tuna were added

2x = y 3x + 15 = 3y y and 3y are the final 1:3 ratio

Now you have a system of equations. I am going to choose the substitution method. "2x" can be substituted for "y" in the second equation:

3x + 15 = 3y

3x + 15 = 3(2x)

3x + 15 = 6x

15 = 3x

5 = x

Egg (final): 2x = 2(5) = 10

Tuna (final): 3x + 15 = 3(5) + 15 = 15 + 15 = 30

Egg (final) + Tuna (final) = Total sandwiches

10 + 30 = 40