Answer:
200 N/C
Step-by-step explanation:
Given that the length of a 60 W, 240 & Omega light bulb filament is 60 cm. If the potential difference across the filament is 120 V, what is the strength of the electric field inside the filament?
The parameters needed from the question are:
Potential difference V = 120v
Distance ( Length) = 60 cm
Convert cm to m by dividing it by 100
Distance = 60/100
Distance = 0.6 m
The formula for electric field strength E is:
E = V/d
Where
V = potential difference
d = distance
Substitute those parameters in the formula
E = 120 / 0.6
E = 1200 / 6
E = 200 N/C
Therefore, the strength of the electric field inside the filament is 200N/C