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1 vote
Find the angle between the given vectors to the nearest degree.

a. 110.7

b.71.6

c. 108.4

d. 112.3

Find the angle between the given vectors to the nearest degree. a. 110.7 b.71.6 c-example-1

2 Answers

5 votes
I believe the answer is c
User Andrew Halloran
by
6.4k points
4 votes

Answer:

c. 108.4

Explanation:

cos theta = (u dot v)/ (||u|| ||v||)

where dot stands for dot product and || || is the magnitude

u = (1,5) v= (7,-4)

u dot v = (1*7 + 5*-4) = 7-20 = -13

||u|| = sqrt( 1^2 +5^2) = sqrt(1+25) = sqrt(26)

||v|| = sqrt(7^2 + (-4)^2) = sqrt(49+16) = sqrt(65)


cos theta = -13/ sqrt(26) sqrt(65)

cos theta = -13 /sqrt(1690)

theta = arccos (-13/sqrt(1690))

theta = 108.43

User John Ryann
by
5.6k points