Question

No wait... That's still not right... The cart was at the point x = 2.8 when t = 0.0 s, but it already had an initial velocity of 1.8 m/s. Now using this information (and that's the last correciton, honest),what was the position of the cart when t = 3.0 s?

Answer 1

Velocity of cart at t = 0 s is, u = 1.8 m/s .

Distance covered in 3 seconds is :

d = 1.8 m/s × 3 s

d = 5.4 m.

So, position of cart after t = 3 seconds is x = 2.8 + 5.4 m = 8.2 m .

Hence, this is the required solution.