Question

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y=2(x+3)^2+4

Vertex ( )

The parabola is opening up or down?
The axis of symmetry:

Answer 1

vertex(-3,4)

Parabola opens up

Axis of symmetry x=-3

Explanation:

`y=2(x+3)^2+4`

Given equation is in the form of

`y=a(x-h)^2 + k`

Vertex is (h,k)

now we compare the general equation with the given equation

a=2 , h=-3 and k=4

We know vertex is (h,k)

so vertex is (-3,4)

a=2, a is positive so parabola opens upwards

Axis of symmetry lies at x=h

So axis of symmetry at x=-3