Question

Find the equation of a parabola with vertex at the origin and focus (0, -32).

y^2= -128x
x^2= -32y
x^2= 128y
x^2=-128y

Answer 1

x^2 = -128y

Explanation:

The general formula for this type of parabola is x^2 = 4ay where a is the y coordinate of the focus. So 4a = 4*-32 = 1-28.

So the answer is x^2 = -128y