165k views
3 votes
Q.16 please
With steps

Q.16 please With steps-example-1
User Mentakatz
by
6.2k points

1 Answer

2 votes

The equations


2x^2+9x-5=0

and


2\left(t-\frac12\right)^2+9\left(t-\frac12\right)-5=0

are really the same, we're just setting
x=t-\frac12, or
t=x+\frac12.


2x^2+9x-5=(2x-1)(x+5)=0\implies x=\frac12,x=-5

So we get


t=\frac12+\frac12=1,t=-5+\frac12=-\frac92

User Babyburger
by
7.2k points