Answer:
6
y
+
3
=
−
4
y
2
Move
4
y
2
to the left side of the equation by adding it to both sides.
6
y
+
3
+
4
y
2
=
0
Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)
2
a
Substitute the values
a
=
4
,
b
=
6
, and
c
=
3
into the quadratic formula and solve for
y
.
−
6
±
√
6
2
−
4
⋅
(
4
⋅
3
)
2
⋅
4
Simplify.
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y
=
−
3
±
i
√
3
4
Explanation: