Question

The formula for a buffer solution contains 1.24% w/v of boric acid. How many milliliters of a 5% w/v boric acid solution should be used to obtain the boric acid needed in preparing 1 L of the buffer solution

Answer 1

248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

Step-by-step explanation:

We can calculate the volume of the 5% w/v boric acid solution needed to prepare the buffer solution 1.24% w/v using the following equation:

`C_(i)V_(i) = C_(f)V_(f)`

Where:

`C_(i)`: is the concentration of the initial solution = 5% w/v

`C_(f)`: is the concentration of the final solution = 1.24% w/v

`V_(i)`: is the volume of the initial solution =?

`V_(f)`: is the volume of the final solution = 1 L

Hence, the volume of the 5% solution is:

`V_(i) = (C_(f)V_(f))/(C_(i)) = (1.24 \%*1 L)/(5 \%) = 0.248 L = 248 mL`

Therefore, 248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

I hope it helps you!