Question

The number of wins and losses of two local basketball teams are shown in the table. Find the probability that a randomly selected game from the season was played by the wolves, given that it was a loss.

----inserted table-----
wins Losses
Wolves 18 12
Hawks 14 16

Answer choices---
0.533
0.200
0.429
0.400

Answer 1

Explanation:

it is c good luck on the rest of your test

Answer 2

Answer: 0.429

Explanation:

From the given table, the total number of games were loss = 12+16=28

The number of games was played by the wolves and was a loss = 12

The total number of games played = 18+12+16+14=60

Now, the probability of games was played by the wolves and was a loss is given by ;-

`\text{P(wolf and loss)}=(12)/(60)=(1)/(5)`

The probability of games that were loss is given by :-

`\text{P(loss)}=(28)/(60)=(7)/(15)`

Now, the probability that a randomly selected game from the season was played by the wolves, given that it was a loss is given by :-

`=\frac{\text{P(wolf and loss)}}{\text{P(loss)}}\\\\=((1)/(5))/((7)/(15))\\\\\\=(3)/(7)=0.428571428571\approx0.429`