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from right circular cylinder with height 10 cm and radius of base 6 CM a right circular cone of the same height and base is remote find the volume of the remaining solid

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Answer:

753.98 cubic cm.

Explanation:

We have been given that from right circular cylinder with height 10 cm and radius of base 6 cm, a right circular cone of the same height and base is removed.

To find the area of remaining solid we will subtract volume of cone from volume of cylinder.


\text{Volume of remaining solid}=\text{Volume of cylinder- Volume of cone}


\text{Volume of remaining solid}=\pi r^(2) h- (1)/(3)\pi r^(2)h


\text{Volume of remaining solid}=(3)/(3)\pi r^(2) h- (1)/(3)\pi r^(2)h


\text{Volume of remaining solid}=(2)/(3)\pi r^(2) h

Upon substituting our given values in the formula we will get,


\text{Volume of remaining solid}=(2)/(3)\pi*6^(2)*10


\text{Volume of remaining solid}=(2)/(3)\pi*36*10


\text{Volume of remaining solid}=2*\pi*12*10


\text{Volume of remaining solid}=240\pi


\text{Volume of remaining solid}=753.9822368615503772\approx 753.98

Therefore, the volume of remaining solid is 753.98 cubic cm.


User Vijay Maheriya
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