Question

Determine the molarity of a solution made by dissolving 8.36g of MgCl2 in water where the final volume of the solution is 500.0mL

Answer 1

Answer : The molarity of solution is, 0.878 mole/L

Solution : Given,

Mass of
`MgCl_2` = 8.36 g

Volume of solution = 500 ml

Molar mass of
`MgCl_2` = 95.2 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

`Molarity=(w* 1000)/(M* V_s)`

where,

w = mass of
`MgCl_2` (solute)

M = molar mass of
`MgCl_2`

`V_s` = volume of solution in liter

Now put all the given values in this formula, we get the molarity of a solution.

`Molarity=((8.36g)* 1000)/((95.2g/mole)* (500L))`

`Molarity=0.878mole/L`

Therefore, the molarity of solution is, 0.878 mole/L