Question

A ball is thrown horizontally from the top of a 73.9-m building and lands 183 m from the base of the building. Ignore air resistance. How long is the ball in the air

Answer 1

t = 3.88 seconds

Step-by-step explanation:

Given that,

A ball is thrown horizontally from the top of a 73.9-m building and lands 183 m from the base of the building.

We need to find the time for which the ball is in air. Let the time be t.

`y=y_o+ut+(1)/(2)at^2`

Here, a = -g,
`y_o=73.9\ m` and y = 0

u is initial velocity, u = 0

`y_o=(1)/(2)gt^2\\\\t=\sqrt{(2y_o)/(g)}\\\\t=\sqrt{(2* 73.9)/(9.8)}\\\\t=3.88\ s`

So, the ball is in the air for 3.88 seconds.