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An object is launched from ground level with an initial velocity of 400 feet per second. To the nearest tenth of a second, how long does it take the object to reach a height of 650 feet? [Use the formula h = -16t2 + v0t + s0.]

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Answer:

650=-16t^2+400t+0

t=1.74sec or 23.25sec(rejected)



User Rohit Malish
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