Answer:
1:c
let x be the distance
12^2=10^(2) + x^(2)
x=6.6332
2.D
length of 2->3 and 2->1 is 90ft, they are perpendicular
by using Pythagorus theorem
the diagonal of the square = square root of the sum of 90^2 +90^2
=127.279ft
3.B
12^2 -6^2 = 10.39ft
Explanation: