We can rewrite the expression under the radical as

then taking the fourth root, we get
![\sqrt[4]{\left(\frac32a^2b^3c^4\right)^4}=\left|\frac32a^2b^3c^4\right|](https://img.qammunity.org/2019/formulas/mathematics/middle-school/gum2otyftwox8i40w4zjq0i61uiw9n7uom.png)
Why the absolute value? It's for the same reason that

since both
and
return the same number
, and
captures both possibilities. From here, we have

The absolute values disappear on all but the
term because all of
,
and
are positive, while
could potentially be negative. So we end up with
