Question

Angle 0 is in the second quadrant, and sin 0=3/5

Answer 1

ANSWER


The value of theta in the second quadrant is,


`143.1 \degree`


Step-by-step explanation

The given trigonometric equation is

`\sin( \theta) = (3)/(5)`


This implies that,



`\theta= arcsin((3)/(5) )`


This implies that the principal solution is

`\theta = 36.9 \degree`
and it is an angle in the first quadrant.

But the solution we are looking for is an angle in the second quadrant.



This is given by

`180 - \theta = 180 - 36.9 = 143.1 \degree`