Question

What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2

Answer 1

D=1

Explanation:

Answer 2

d=1

Explanation:

`(-3d)/(d^2-2d-8) +(3)/(d-4) =(-2)/(d+2)`

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

`(-3d)/((d-4)(d+2)) +(3)/(d-4) =(-2)/(d+2)`

Now make the denominators same

LCD: (d-4)(d+2)

`(-3d)/((d-4)(d+2)) +(3(d+2))/((d-4)(d+2)) =(-2(d-4))/((d+2)(d-4))`

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1