Question

Write an expression that represents the width of a rectangle with length x+5 and area +^3+12^2+47x+60

Answer 1

So, the width of rectangle is

`W=x^2+7x+12`

Explanation:

We are given area

`A=x^3+12x^2+47x+60`

length is

`L=(x+5)`

we know that formula of area of rectangle as

`A=L* W`

where

A is area of rectangle

W is width of rectangle

L is length of rectangle

so, we can plug value

`x^3+12x^2+47x+60=(x+5)* W`

now, we can solve for W

`W=(x^3+12x^2+47x+60)/((x+5))`

we can use synthetic division

so, we got

`W=(x^3+12x^2+47x+60)/((x+5))=x^2+7x+12`