Question

HELP ASAP 20 POINTS

11)The solubility of calcium carbonate is 14 . This rate means that 14 milligrams of calcium carbonate can dissolve in 1 liter of water. How much water would be required to fully dissolve 11 grams of calcium carbonate? Express your answer to the correct number of significant figures. One milligram is equal to 0.001 grams. It would take liters of water to fully dissolve 11 grams of calcium carbonate.

Answer 1

790

It would take 790 liters of water to fully dissolve 11 grams of calcium carbonate.

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Answer 2

Solubility of a compound in water can be referred to as the amount of the compound that can be dissolved in 1 L of the solvent (water) at any given temperature. Solubility of a compound can be expressed in the units of g/L or mg/L.

Given that the solubility of calcium carbonate in water = 14 mg/L

We have to calculate the volume of water that can dissolve 11 g of calcium carbonate.

Converting 11 g calcium carbonate to mg:

`11g *(1000mg)/(1g) =11,000 mg`

Volume of water that would dissolve 11000 mg calcium carbonate

=
`11000 mg CaCO_(3)*(1L)/(14 mg)`

=785.7 L

Rounding the volume 785.7 L to two significant figures, we get 790 L water.

Therefore, we would need 790 L water to completely dissolve 11 g of calcium carbonate.