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What is the restriction of x^2-6x+5/x^2-3x-10

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Answer:

x ≠ - 2, 5

Explanation:

The restrictions occur in the denominator which cannot be zero as this would make the function undefined. Equating the denominator to zero and solving gives the values that x cannot be.

solve x² - 3x - 10 = 0 ⇒ (x - 5(x + 2) = 0 ⇒ x = -2, 5


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