Answer:
ΔQ = 5054 KJ/kg.K
Step-by-step explanation:
First of all, we will find the value of the specific heat of hydrogen. Since it is mentioned that the value of specific heat is constant between 300 K and 650 K. Therefore, we can take it to be the average of values at these two temperatures.
C = 14.44 KJ/ kg.K
Now, the heat absorbed is given by the following formula:
![\Delta Q = C(T_(f) - T{i})](https://img.qammunity.org/2022/formulas/physics/college/9j56z3p44zn9px8cladchnt1xgd5kb6htn.png)
where,
T_f = Final Temperature = 650 K
T_i = Initial Temperature = 300 K
![\Delta Q = (14.44\ KJ/kg.K)(650\ K - 300\ K)\\](https://img.qammunity.org/2022/formulas/physics/college/5y7s402j1d91eb53fhlt94jw7ikhaw1g78.png)
ΔQ = 5054 KJ/ kg.K