Question

Express the area of a rectangle with length 11y^411y 4 11, y, start superscript, 4, end superscript and width y^2y 2 y, start superscript, 2, end superscript as a monomial.

Answer 1

Area of rectangle =
`11y^6`

Explanation:

Let l be the length of rectangle and w is the width of rectangle respectively.

Given: Length of rectangle is
`11y^4` and width of rectangle is
`y^2`

⇒
`l =11y^4` and
`w =y^2`

To find the area of rectangle:

Area of Rectangle(A) is equal to multiply its length by its width.

i.e,
`A = l * w`

Substitute the given values of l and w in above formula we get;

`A = 11y^4 * y^2`

We know that:
`a^n * a^m = a^(n+m)`

Then;

`A = 11y^(4+2)= 11y^6`

therefore, the area of rectangle is,
`11y^6`