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What is the [oh-] in a solution with a poh of 11.25
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What is the [oh-] in a solution with a poh of 11.25

User Entonio
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2 Answers

6 votes

Answer:

5.62*10^-12

Step-by-step explanation:

Acellus

User Carlos Negron
by
7.2k points
3 votes

The [Oh-] in the solution with a POh of 11.25 is 5.623 x 10^-12 M


calculation

POH= - log [ OH-]

Therefore - log [oH-] =11.25

To calculate [oh-] concentration find the antilog of 11.35

= 10^- 11.25 = 5.623 x 10^-12 M


User Tom Deleu
by
7.6k points
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