Question

2. Mrs. Ferguson is considering reserving a room at the Abraham Hotel. The Abraham Hotel charges $239 a night. (a) Mrs. Ferguson originally planned to spend $1000 for the hotel stay. For how many nights could she book the hotel room? Show your work. (b) Mrs. Ferguson calculates that 6 nights will cost $1450. What is the percent error in Mrs. Ferguson’s calculation? Round to the nearest percent. Show your work. (c) Mrs. Ferguson looked at another hotel. She waited a week before she decided to book nights at that hotel, and now the prices have increased. The original price was $1589. The price for the same room and same number of nights is now $2075. What is the percent increase? Round to the nearest percent. Show your work. (d) Mr. Ferguson suggested contacting a travel agent to see whether they could get a lower price. The agent found a price that was 30% lower than $2075. What was the price the travel agent found? Show your work.

Answer 1

a) 4 nights

b) 31%

c) 31%

d) $1452.50

Explanation:

Abraham Hotel charges per night $239.

a. Mrs. Ferguson originally planned to spend $1000 for the hotel stay.

Number of nights = $1000/$239 = 4.18 nights

Nights cannot be decimal, so the answer must be whole number.

Mrs.Ferguson can stay 4 nights

b. Here we have to use the formula.

The percent of error = theoretical value – measured value/theoretical value x 100

Percent error = [($1450 – $1000)/$1450]x100

= (450/1450)*100

= 45000/1450

= 31%

c. Percent of increase = (Increase)/original amount * 100

= [($2075 - $1589)/$1589]*100

= (486/1589)*100

= 31%

d. Now we have to find 30% of 2075

= 30% * 2075

= 0.3 *2075

= $622.5

Now subtract 622.5 from $2075

The price the travel agent found = $2075 - $622.5

=$1452.50

Thank you.