Answer:
1/2 ; 1/3 ; 1/6
Explanation:
Given :
Ben ~ exp(1)
Max ~ exp (2)
Yolanda ~ exp(3)
Ben :
X ~ exp(1)
Max:
Y ~ exp(2)
Yolanda :
Z ~ exp(3)
Probability that Yolanda is served first :
P(Z < (X, Y)) = Z /(x + y + z) = 3 /(1 + 2 + 3) = 3/6 = 1/2
Probability that Ben is served before Yolanda :
P(X < Z) = 1/ (1 + 2) = 1/3
Expected waiting time for first person served :
First person served = 1
Total = (1 + 2 + 3) = 6
Expected waiting time; E(x) :
E(x) : 1 / 6