Question

The distance between two consecutive nodesof a standing wave is 20.9cm.Thehandgen-erating the pulses moves up and down throughacompletecycle2.57 times every 4.47 s.Find the velocity of the wave.

Answer 1

Velocity, v = 0.239 m/s

Step-by-step explanation:

Given that,

The distance between two consecutive nodes of a standing wave is 20.9 cm = 0.209 m

The hand generating the pulses moves up and down through a complete cycle 2.57 times every 4.47 s.

For a standing wave, the distance between two consecutive nodes is equal to half of the wavelength.

`(\lambda)/(2)=0.209\ m\\\\\lambda=0.418\ m`

Frequency is number of cycles per unit time.

`f=(2.57)/(4.47)\\\\f=0.574\ Hz`

Now we can find the velocity of the wave.

Velocity = frequency × wavelength

v = 0.574 × 0.418

v = 0.239 m/s

So, the velocity of the wave is 0.239 m/s.