130k views
3 votes
If sinθ= 1/2, and 0°<θ<180°, the smaller value of θ is __° and the larger value of θ is __°.

User Anuki
by
6.7k points

2 Answers

7 votes

Answer:

Smaller value - 30; Larger value - 150

Explanation:

This is shown on a Radian Circle.

To prove that this is true sin(30) = 1/2 & sin(150) = 1/2

If sinθ= 1/2, and 0°<θ<180°, the smaller value of θ is __° and the larger value-example-1
User SuperShoot
by
6.0k points
4 votes

Answer: the smaller value of θ is 30° and the larger value of θ is 150°.

Explanation:

We know, for the notable angles and values of the trigonometric functions (you can find a lot of tables of it) that sin(30°) = 1/2 and also that sin(150°) = 1/2

Then if 0°<θ<180°, the smallest value of θ is 30°, and the biggest value is 150°

You also can use the inverse function

if sinθ= 1/2

then θ= asin(1/2)

User Bayeni
by
5.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.