Question

Calculate the volume in mL of 1.043 M acetic acid (CH3COOH) that is needed to prepare 50.0 mL of 0.10 M acetic acid. Show your work and give your answer to the correct number of significant figures.

Answer 1

Answer: 4.8 mL of 1.043 M acetic acid that is needed to prepare 50.0 mL of 0.10 M acetic acid

Step-by-step explanation:

According to the dilution law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock
`CH_3COOH` solution = 1.043 M

`V_1` = volume of stock
`CH_3COOH` solution = ?

`M_1` = molarity of diluted
`CH_3COOH` solution = 0.10 M

`V_1` = volume of diluted
`CH_3COOH`solution = 50.0 ml

Putting in the values we get:

`1.043* V_1=0.10* 50.0`

`V_1=4.8ml`

Therefore, volume in mL of 1.043 M acetic acid (CH3COOH) that is needed to prepare 50.0 mL of 0.10 M acetic acid is 4.8