Question

The Question A 1.80 x 10-2 kg block of metal has the following dimensions: 0.4981 inches by 0.531 inches, by 0.5839 inches. Determine the density of the block in g/mL. Using the provided list of metals and their respective densities, what is the metal's identity

Answer 1

Zinc

Step-by-step explanation:

m = Mass of block
`1.8* 10^(-2)\ \text{kg}=18\ \text{g}`

Dimension of block is 0.4981 inches by 0.531 inches, by 0.5839 inches

`1\ \text{inch}^3=16.3871\ \text{mL}`

Volume of block

`V=0.4981* 0.531* 0.5839* 16.3871\ \text{mL}`

Density is given by

`\rho=(m)/(V)\\\Rightarrow \rho=(18)/(0.4981* 0.531* 0.5839* 16.3871)\\\Rightarrow \rho=7.112\ \text{g/mL}`

The density of the metal is
`7.112\ \text{g/mL}`. The metal here is zinc.