Question

A bullet of .05 kg is fired into a block of wood. Knowing that the bullet left the gun with a muzzle velocity of 350. m/s, and the bullet penetrates .15 m into the block of wood, determine:

Answer 1

We know, Impulse of a body is change in momentum.

Also, the final velocity of wood block is 0 m/s.

So, Impulse = Final Momentum - Initial Momentum

Impulse = 0 - ( 0.05 kg × 350 m/s )

Impulse = - 17.5 kg m/s

Therefore, the impulse exerted by the wood on the bullet is -17.5 kg m/s .