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Write an equation in point slope form for the line trough the given point with the given slope. (4, -6); m=3/5

User NAbbas
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\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies \cfrac{3}{5} \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=\cfrac{3}{5}(x-4)\implies y+6=\cfrac{3}{5}(x-4)

User Trevor Abell
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