Question

Which of the following would represent a single displacement reaction between Potassium Bromide (K^+Br^-) and Iodine (I), which forms iodide (I^-)?

options:
KBr + I -> K + IBr
KBr + I -> KBr + I
KBr + I -> KI + Br

Answer 1

KBr + I -> Kl + Br

Step-by-step explanation:

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Answer 2

Option : KBr + I -> KBr+I

Step-by-step explanation:

Single-replacement reaction or single displacement reactions are a type of chemical reactions in which a whole compound reacts with an element in such a way that the element takes place of one of the compound's own elements and sets it free.

If we talk about KBr and I displacement reaction is not possible among these because Iodine is less reactive than Bromine that is why it will not react with KBr or replace Br.

KBr + I -> KBr+ I

Potassium Bromide + Iodine -> Potassium bromide + Iodine

Hope it help!